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Question

Write the equation of the plane passing through (2, −1, 1) and parallel to the plane 3x + 2y −z = 7.

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Solution

Let the equation of a plane parallel to the given plane be 3x+2y-z=k ... 1This passes through (2, -1, 1). So, 3 2+2 -1-1=kk=3Substituting this in (1), we get3x+2y-z=3, which is the equation of the required plane.

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