Question

Write the equation of the plane whose intercepts on the coordinate axes are 2, −3 and 4.

Answer 1

$$\begin{gathered} \text{We know that the equation of the plane with a, b and c intercepts on the coordianate axes is given by} \\ \frac{x}{a}+\frac{y}{b}+\frac{z}{c}=1 \\ \text{Given that} \\ a=2;b=-3;c=4 \\ \text{So, the equation of the required plane is} \\ \frac{x}{2}+\frac{y}{-3}+\frac{z}{4}=1 \\ \Rightarrow 6x-4y+3z=12 \end{gathered}$$