Write the equation when aqueous ammonia reacts with mercury (I) chloride.

2 H g_{2} C l_{2} + N H_{3} \to 4 H g C l + H g N H_{2} + N H_{4}

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H g C l + N H_{3} \to H g N H_{2} C l + N H_{2} C l

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2 H g C l + N H_{3} \to 2 H g + N H_{2} C l + N H_{4} C l

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H g_{2} C l_{2} + N H_{3} \to H g + H g N H_{2} C l + N H_{4} C l

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Solution

The correct option is D $H g_{2} C l_{2} + N H_{3} \to H g + H g N H_{2} C l + N H_{4} C l$
When mercury (I) chloride reacts with aqueous ammonia, then there is the formation of $H g, H g N H_{2} C l$ and $N H_{4} C l$ .
The reaction is as follows:
$H g_{2} C l_{2} + N H_{3} \to H g + H g N H_{2} C l + N H_{4} C l$

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H g_{2} C l_{2} + N H_{3} \to H g + H g N H_{2} C l + N H_{4} C l

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N H_{3} + C l_{2} \to N_{2} + N H_{4} C l

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