Question

Write the equations for reaction of chlorine with the following:
(a) Cold and dilute NaOH (b) Excess $N{H}_3$
(c) $Ca(OH{)}_2$ (d) $N{a}_2{S}_2{O}_3$

Answer 1

Reaction of chlorine with-

• (a) Cold and dilute $NaOH$:
  

When chlorine reacts with cold and dilute solution of sodium hydroxide the products obtained are ${Cl}^{-}+{ClO}^{-}$.

${Cl}_2+\underset{\left(\text{Cold and dilute}\right)}{2NaOH}⟶NaCl+NaOClO$

• (b) Excess $NaOH$:
  

Chlorine reacts with excess ammonia to give ammonium chloride $\left(N{H}_{4}Cl\right)$ and Nitrogen gas.

$3{Cl}_2+\underset{\left(\text{Excess}\right)}{8N{H}_3}⟶6N{H}_{4}Cl+N_2$

• (c) $Ca{\left(OH\right)}_2$:
  

Dry slaked lime with chlorine is used to prepare bleaching powder.

${Cl}_2+Ca{\left(OH\right)}_2⟶CaO{Cl}_2+Ca{Cl}_2+HCl$

The mixture is known as bleaching powder.

• (d) ${Na}_2{S}_2{O}_3$:
  

Sodium thiosulfate react with chlorine and water to produce sulphur, hydrogen chloride and sodium sulphate.

${Cl}_2+{Na}_2{S}_2{O}_3⟶{Na}_{2}S{O}_4+HCl+S$