Write the equations of the lines (i) PQ (ii) RS (iii) CD (iv) MN (v) XX (vi) YY'

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Solution

(i) Line PQ is parallel to X-axis and is at a distance of 3.5 units from X-axis in the positive direction of Y-axis.
Therefore equation of PQ is y = 3.5.

(ii) Line RS is parallel to Y-axis and is at a distance of 6 units from Y-axis in the positive direction of X-axis.
Therefore equation of RS is x = 6.

(iii) Line CD is parallel to Y-axis and is at a distance of 3 units from Y-axis in the negative direction of X-axis.
Therefore equation of CD is x = $-$ 3.

(iv) Line MN is parallel to X-axis and is at a distance of 5 units from X-axis in the negative direction of Y-axis.
Therefore equation of MN is y = $-$ 5.

(v) Line X'X is X-axis.
And the equation of X-axis is y = 0.
Therefore equation of X'X is y = 0.

(vi) Line YY' is Y-axis.
And the equation of Y-axis is x = 0.
Therefore equation of YY' is x = 0.

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Q. Answer the questions with the help of the fig. 5.36

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Steps for constructing a line segment whose length is equal to the difference of the lengths of the two given line segments are:

(i) Now draw a line L.

(ii) Take two line segments AB and CD.

(iii) With P as a centre cut a length PZ equal to AB.

(iv) SZ is the required line Segment.

(v) Mark point P on the line L.

(vi) Now from P cut a length PS equal to CD.

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Write the equations of the lines (i) PQ (ii) RS (iii) CD (iv) MN (v) XX (vi) YY' figure

Write the equations of the lines (i) PQ (ii) RS (iii) CD (iv) MN (v) XX (vi) YY'

figure