Write the expression for MI of a ring and disc of mass M and radius R about an axis passing through its center and perpendicular to its plane.

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Solution

Dear Student ,
The expression of moment of inertia of a ring and a disc of mass M and radius R about an axis passing through its centre and perpendicular to its plane is
I_ring = MR²and I_disc = $\frac{1}{2} M R^{2}$
Regards

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Q. Moment of Inertia

(M I)

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I_{1} = M I

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I_{4} = M I

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Then :

A ring has greater moment of inertia than a circular disc of same mass and radius, about an axis passing through its centre of mass perpendicular to its plane, because

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Write the expression for MI of a ring and disc of mass M and radius R about an axis passing through its center and perpendicular to its plane.

Dear Student , The expression of moment of inertia of a ring and a disc of mass M and radius R about an axis passing through its centre and perpendicular to its plane is Iring = MR2 and Idisc = 12MR2 Regards

Dear Student ,
The expression of moment of inertia of a ring and a disc of mass M and radius R about an axis passing through its centre and perpendicular to its plane is
I_ring = MR²and I_disc = $\frac{1}{2} M R^{2}$
Regards