Write the expression for the equilibrium constant ${(K}_{c})$ for the reaction :
${C H}_{3} {C O O C}_{2} H_{5} (a q) + H_{2} O (I) ⇄ {C H}_{3} C O O H (a q) + C_{2} H_{5} O H (a q)$

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Solution

$C H_{3} C O O C_{2} H_{5} (a q) + H_{2} O (l) ⇌ C H_{3} C O O H (a q) + C_{2} H_{5} O H (a q)$
Here, water is in excess and in pure liquid state, So, not considered in $K_{C}$ .
$K_{c} = \frac{[C H_{3} C O O H] [C_{2} H_{5} O H]}{[C H_{3} C O O C_{2} H_{5}]}$

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