Write the expression for the heat energy $Q$ received by $m$ kg of a substance of specific heat capacity $c J k g^{- 1} K^{- 1}$ when it is heated through $Δ t^{\circ} C$

Q = \frac{m c}{Δ t} J

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Q = \frac{m}{c Δ t} J

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Q = \frac{1}{m c Δ t} J

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Q = m c Δ t J

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Solution

The correct option is C $Q = m c Δ t J$
Heat energy received is $Q = c \times m \times Δ t = m c Δ t J$

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Similar questions

The amount of heat require to raise the temperature of mass M of a substance through ∆T is

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List I	List II
A. Specific Heat Capacity	$1. \frac{△ Q}{△ T}$
B. Thermal Capacity	$2. \frac{△ Q}{m . △ T}$
C. Heat required for the Change of state	$3. m . C$
D. Water equivalent	$4. m L$

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