Write the first five terms in each of the following sequence:
$a_{1} = 1, a_{n} = a_{n - 1} + 2, n > 1$

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Solution

$\begin{matrix} a_{1} = 1 a_{n} = a_{n - 1} + 2, n > 1 p u i t n = 2 a_{2} = a_{2 - 1} + 2 = a_{1} + 2 = 1 + 2 = 3 h = 3 a_{3} = a_{3 - 1} + 2 = a_{2} + 2 = 3 + 2 = 5 x = 4 a_{4} = a_{4 - 1} + 2 = a_{3} + 2 = 5 + 2 = 7 n = 5 a_{5} = a_{5 - 1} + 2 = a_{4} + 2 7 + 2 = 9 s o, 1, 2, 5, 7, 9 a n s . \end{matrix}$

Hence, this is the answer.

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Similar questions

a_{1} = - 1, a_{n} = \frac{a_{n - 1}}{n + 2}, n > 1

\forall n ϵ N

a_{1} = 1 = a_{2}, a_{n - 1} + a_{n - 2}, n > 2

a_{1} = a_{2} = 2, a_{n}

= a_{n - 1} - 1, n > 2

Write the first five terms of each of the sequences in obtain the corresponding series :

$a_{1} = a_{2} = 2, a_{n} = a_{n - 1} - 1, n > 2$

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