Write the first five terms of the sequences whose $n^{t h}$ term is :

$a_{n} = 2^{n}$

Open in App

Solution

Here $a_{n} = 2^{n}$

Putting n = 1, 2, 3, 3 and 5, we have

$a_{1} = 2^{1} = 2 a_{2} = 2^{2} = 4$

$a_{3} = 2^{3} = 8 a_{4} = 2^{4} = 16$

$a_{5} = 2^{5} = 32$

Thus, terms of the sequence are : 2, 4, 8, 16 and 32.

Suggest Corrections

Similar questions

n^{t h}

a_{n} = 2^{n}

n^{t h}

a_{n} = 2^{n}

n^{t h}

a_{n} = \frac{2 n - 3}{6}

Write the first five terms of the sequences whose $n^{t h}$ term is

$a_{n} = n (n + 2)$

Write the first five terms of the sequences whose $n^{t h}$ term is :

$a_{n} = n \frac{n^{2} + 5}{4}$

Join BYJU'S Learning Program