Write the first four terms of each of the following sequences whose $n^{t h}$ term are $a_{n} = n^{2} - n + 1$

Open in App

Solution

Sequence:
A sequence is an ordered list of any objects or a set of numbers in a particular order followed by some condition.
Given data:
Given $n^{t h}$ term is $a_{n} = n^{2} - n + 1$
Calculation:
Putting $n = 1, 2, 3, 4$ in $a_{n} = n^{2} - n + 1$ we get,
$a_{1} = 1^{2} - 1 + 1 = 1 - 1 + 1 = 0 + 1 = 1 a_{2} = 2^{2} - 2 + 1 = 4 - 2 + 1 = 2 + 1 = 3 a_{3} = 3^{2} - 3 + 1 = 9 - 3 + 1 = 6 + 1 = 7 a_{4} = 4^{2} - 4 + 1 = 16 - 4 + 1 = 12 + 1 = 13$
Conclusion:
Thus, the required first four terms of the sequence defined by $a_{n} = n^{2} - n + 1$ are $1, 3, 7, 13 .$

Suggest Corrections

Similar questions

a_{n} = \frac{n - 3}{3}

a_{n} = \frac{3 n - 2}{5}

a_{n} = \frac{n (n - 2)}{2}

a_{n} = \frac{2 n - 3}{6}

\frac{n^{2}}{n + 1}

n^{t h}

a_{n} = 3 n + 2

n

a_{n} = n^{2} - n + 1

Write the first five terms of the sequences whose $n^{t h}$ term is:

$a_{n} = \frac{n}{n + 1}$

Join BYJU'S Learning Program