Write the first four terms of the AP, when the first term $a$ and the common difference $d$ are given as follows: $a = 4, d = - 3$ .

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Solution

Find the first four terms of the AP:
It is given that $\begin{array}{rcl} a & = & 4, d = - 3 \end{array}$
Formula for $n^{t h}$ term of an AP is given by, $\begin{array}{rcl} a_{n} & = & a + (n - 1) d \end{array}$
Now,
$\begin{array}{rcl} a_{1} & = & 4 + (1 - 1) (- 3) \\ \Rightarrow & a_{1} = 4 \\ a_{2} & = & 4 + (2 - 1) (- 3) \\ \Rightarrow & a_{2} = 1 \\ a_{3} & = & 4 + (3 - 1) (- 3) \\ \Rightarrow & a_{3} = - 2 \\ a_{4} & = & 4 + (4 - 1) (- 3) \\ \Rightarrow & a_{4} = - 5 \end{array}$
Hence, the first four terms of the AP are $4, 1, - 2, - 5$ .

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