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Question

Write the first three terms in each of the sequences defined by the following -
(i) an = 3n + 2
(ii)an = n2 + 1

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Solution

(i)

We have,

an = 3n + 2

Putting n = 1, 2 and 3, we get

a1 = 3 × 1 + 2 = 3 + 2 = 5,

a2 = 3 × 2 + 2 = 6 + 2 = 8,

a3 = 3 × 3 + 2 = 9 + 2 = 11

Thus, the required first three terms of the sequence defined by an = 3n + 2 are 5, 8, and 11.

(ii)

We have,

an= n2 + 1

Putting n = 1, 2, and 3 we get

a1 = 12 + 1 = 1 + 1 = 2

a2 = 22 + 1 = 4 + 1 = 5

a3 = 32 + 1 = 9 + 1 = 10

Thus, the first three terms of the sequence defined by an = n2 + 1 are 2, 5 and 10.


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