Write the first three terms in each of the sequences defined by the following -
(i) an = 3n + 2
(ii)an = n2 + 1
(i)
We have,
an = 3n + 2
Putting n = 1, 2 and 3, we get
a1 = 3 × 1 + 2 = 3 + 2 = 5,
a2 = 3 × 2 + 2 = 6 + 2 = 8,
a3 = 3 × 3 + 2 = 9 + 2 = 11
Thus, the required first three terms of the sequence defined by an = 3n + 2 are 5, 8, and 11.
(ii)
We have,
an= n2 + 1
Putting n = 1, 2, and 3 we get
a1 = 12 + 1 = 1 + 1 = 2
a2 = 22 + 1 = 4 + 1 = 5
a3 = 32 + 1 = 9 + 1 = 10
Thus, the first three terms of the sequence defined by an = n2 + 1 are 2, 5 and 10.