Question

Write the first three terms of the AP when a and d are as given below:

$a=\frac{1}{2},d=-\frac{1}{6}$
first three terms are $\frac{1}{2},\frac{1}{3},\frac{1}{6}$
If true then enter $1$ and if false then enter $0$

Answer 1

As we know the general term of an AP is given by $a_n=a+(n-1)d$
So we have

$a_1=a=\frac{1}{2}$

$a_2=a+d=\frac{1}{2}+\frac{-1}{6}=\frac{1}{3}$

$a_3=a+2d=\frac{1}{2}+2\times \frac{-1}{6}=\frac{1}{6}$

$\therefore 1^{st}$ three terms are,

$\frac{1}{2},\frac{1}{3},\frac{1}{6},..$