Write the first three terms of the sequence an=3n2-2.
Find the first three terms of the sequence an=3n2-2 by substituting n=1,2,3:
⇒a1=3×12-2=1
⇒a2=3×22-2=10
⇒a3=3×32-2=25
The first three terms of the sequence an=3n2-2 is 1,10,25.
Write the first four terms of the sequence whose nth term is
(a) Tn = 2n − 1
(b) Tn = 5 − 2n
(c) Tn = 3n2 + 1
(d) Tn = 3n+1