Question

Write the first three terms of the sequence $a_n=\frac{n-3}{2}$.

Answer 1

Find the first three terms of the sequence $a_n=\frac{n-3}{2}$ by substituting $n=1,2,3$:
$\begin{array}{rcl}& \Rightarrow & a_1=\frac{1-3}{2}\\ & =& \frac{-2}{2}\\ & =& -1\end{array}$

$\begin{array}{rcl}& \Rightarrow & a_2=\frac{2-3}{2}\\ & =& \frac{-1}{2}\end{array}$

$\begin{array}{rcl}& \Rightarrow & a_3=\frac{3-3}{2}\\ & =& 0\end{array}$

Therefore, the first three terms of the sequence is $-1,\frac{-1}{2},0$.