Write the first two terms of the sequence whose $n^{t h}$ term is $t_{n} = 3 n - 4$

Open in App

Solution

Here, $t_{n} = 3 n - 4$
Put $n = 1, t_{1} = 3 (1) - 4 = - 1$
Put $n = 2, t_{2} = 3 (2) - 4 = 2$
$∴$ First two terms are $- 1$ and $2$ .

Suggest Corrections

Similar questions

Write the first four terms of the sequence whose nth term is

(a) T_n = 2n − 1

(b) T_n = 5 − 2n

(d) T_n = 3ⁿ⁺¹

n^{t h}

t_{n} = n + 2

n^{t h}

3 n + 1

n^{t h}

t_{n} = 4 n - 3

n^{t h}

t_{n} = 4 n - 3

Join BYJU'S Learning Program