Question

Write the following as decimals.

$300+40+5+\frac{7}{10}$

Answer 1

Given, $300+40+5+\frac{7}{10}$

So,

$300+40+5+\frac{7}{10}=\left(3\times 100\right)+\left(4\times 10\right)+\left(5\times 1\right)+\left(7\times \frac{1}{10}\right)$

Here, the place value of$3=300$, the place value of$4=40$, the place value of$5=5$, the place value of$7=\frac{7}{10}$

So, In decimal form, $3$ is at hundreds, $4$is at tens place, $5$is at ones,$7$ is at tenths place.

Hence, the required decimal is $345.7$