Question

Write the following equation and balance them.

Barium chloride + Sodium sulphate $\to$ Barium sulphate + Sodium chloride

Answer 1

The reaction can be solved in two steps:

1. Complete the reaction by writing the products.
2. Balance the equation.

1. Complete the reaction by writing the products:

$$\begin{gathered} {\mathrm{BaCl}}_2\left(\mathrm{s}\right)+{\mathrm{Na}}_2{\mathrm{SO}}_4\left(\mathrm{s}\right)\to {\mathrm{BaSO}}_4\left(\mathrm{s}\right)+\mathrm{NaCl}\left(\mathrm{s}\right) \\ (\mathrm{barium}\mathrm{chloride})(\mathrm{Sodium}\mathrm{sulphate})(\mathrm{Barium}\mathrm{sulphate})(\mathrm{sodium}\mathrm{chloride}) \end{gathered}$$

2. Balancing of the reaction by hit and trial method:

A balanced equation is a chemical reaction equation in which the overall charge and the number of atoms for each element in the reaction are the same for both the reactants and the products.

To balance the chemical equation, begin by multiplying the element or compound which has less number of atoms with a number that would make the number equal on both sides.

$$\begin{gathered} {\mathrm{BaCl}}_2\left(\mathrm{s}\right)+{\mathrm{Na}}_2{\mathrm{SO}}_4\left(\mathrm{s}\right)\to {\mathrm{BaSO}}_4\left(\mathrm{s}\right)+\mathrm{NaCl}\left(\mathrm{s}\right) \\ (\mathrm{barium}\mathrm{chloride})(\mathrm{Sodium}\mathrm{sulphate})(\mathrm{Barium}\mathrm{sulphate})(\mathrm{sodium}\mathrm{chloride}) \end{gathered}$$

Types of atoms	Number of atoms on reactant side	Number of atoms on product side
Barium	1	1
Chloride	2	1
Sodium	2	1
Sulphur	1	1
Oxygen	4	4

Balance the equation by multiplying sodium chloride with 2 on product side as the number of sodium atom are less on reactant side.

$$\begin{gathered} {\mathrm{BaCl}}_2\left(\mathrm{s}\right)+{\mathrm{Na}}_2{\mathrm{SO}}_4\left(\mathrm{s}\right)\to {\mathrm{BaSO}}_4\left(\mathrm{s}\right)+2\mathrm{NaCl}\left(\mathrm{s}\right) \\ (\mathrm{barium}\mathrm{chloride})(\mathrm{Sodium}\mathrm{sulphate})(\mathrm{Barium}\mathrm{sulphate})(\mathrm{sodium}\mathrm{chloride}) \end{gathered}$$

Types of atoms	Number of atoms on reactant side	Number of atoms on product side
Barium	1	1
Chloride	2	2
Sodium	2	2
Sulphur	1	1
Oxygen	4	4

As the number of all the atoms is equal on both sides, the chemical equation is now balanced.

So, the overall complete and balanced chemical equation is

$$\begin{gathered} {\mathrm{BaCl}}_2\left(\mathrm{s}\right)+{\mathrm{Na}}_2{\mathrm{SO}}_4\left(\mathrm{s}\right)\to {\mathrm{BaSO}}_4\left(\mathrm{s}\right)+2\mathrm{NaCl}\left(\mathrm{s}\right) \\ (\mathrm{barium}\mathrm{chloride})(\mathrm{Sodium}\mathrm{sulphate})(\mathrm{Barium}\mathrm{sulphate})(\mathrm{sodium}\mathrm{chloride}) \end{gathered}$$