Write the following in exponential form assuming denominators not equal to zero:
$4^{5} \div 4^{2}$

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Solution

For any non-zero integer $a$ , where $m$ and $n$ are whole numbers and $m > n$ .
$a^{m} \div a^{n} = \frac{a^{m}}{a^{n}} = a^{m - n}$
So, $4^{5} \div 4^{2}$ $= 4^{5 - 2}$ where $a = 4, m = 5, n = 2$
$= 4^{3}$ .
Therefore, $4^{5} \div 4^{2}$ $= 4^{3}$ .

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