Write the following in the expanded form.
$(2 a - 3 b - c)^{2}$ .

4 a^{2} + 9 b^{2} + c^{2} + 12 a b - 4 a c + 6 b c

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4 a^{2} + 9 b^{2} + c^{2} - 12 a b - 4 a c - 6 b c

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4 a^{2} + 9 b^{2} + c^{2} - 12 a b + 4 a c + 6 b c

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4 a^{2} + 9 b^{2} + c^{2} - 12 a b - 4 a c + 6 b c

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Solution

The correct option is C $4 a^{2} + 9 b^{2} + c^{2} - 12 a b - 4 a c + 6 b c$
We have, $(2 a - 3 b - c)^{2}$

$= (2 a)^{2} + (- 3 b)^{2} + (- c)^{2} + 2 (2 a) (- 3 b) + 2 (- 3 b) (- c) + 2 (2 a) (- c)$

$= 4 a^{2} + 9 b^{2} + c^{2} - 12 a b + 6 b c - 4 a c$

Suggest Corrections

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4 a^{2} + 9 b^{2} + c^{2} - 12 a b - 6 b c + 4 a c

4 a^{2} + 9 b^{2} + c^{2} - 12 a b - 6 b c + 4 a c

4 a^{2} + 9 b^{2} + c^{2} - 12 a b + 6 b c - 4 a c

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2 a + 3 b + 5 c

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