Write the following in the expanded form.
$(a + 2 b + c)^{2}$ .

a^{2} + 4 b^{2} + c^{2} + 2 a b + 4 b c + 2 a c

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a^{2} + 4 b^{2} + c^{2} + 4 a b + 4 b c + 2 a c

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a^{2} + 4 b^{2} + c^{2} + 4 a b + 2 b c + 2 a c

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a^{2} + 4 b^{2} + c^{2} + 4 a b + 4 b c + 4 a c

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Solution

The correct option is B $a^{2} + 4 b^{2} + c^{2} + 4 a b + 4 b c + 2 a c$
$(a + 2 b + c)^{2}$
$= a^{2} + (2 b)^{2} + c^{2} + 2 (a) (2 b) + 2 (a) (c) + 2 (2 b) (c)$
$a^{2} + 4 b^{2} + c^{2} + 4 a b + 2 a c + 4 b c$
$a^{2} + 4 b^{2} + c^{2} + 4 a b + 4 b c + 2 a c$

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Similar questions

△ A B C, 2 a^{2} + 4 b^{2} + c^{2} = 4 a b + 2 a c

cos B

Δ A B C

2 a^{2} + 4 b^{2} + c^{2} = 4 a b + 2 a c .

A B C, 2 a^{2} + 4 b^{2} + c^{2} = 4 a b + 2 a c,

cos B

A B C

2 a^{2} + 4 b^{2} + c^{2} = 4 a b + 2 a c

cos B

Factorise:

$4 a^{2} - (4 b^{2} + 4 b c + c^{2})$

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