Question

Write the following in the expanded form:

(iii)$(-3x+y+z{)}^2$

Answer 1

Given, $(-3x+y+z{)}^2$
Using Identity,
$(a+b+c{)}^2=a^2+b^2+c^2+2ab+2bc+2ca$
$\therefore (-3x+y+z{)}^2$
$=(-3x{)}^2+y^2+z^2+2\times -3x\times y+2\times y\times z+2\times z\times -3x$
$=9x^2+y^2+z^2-6xy+2yz-6zx$

Hence, $(-3x+y+z{)}^2=9x^2+y^2+z^2-6xy+2yz-6zx.$