Question

Write the following in the expanded form:

(xii) $(-2x+3y+2z{)}^2$

Answer 1

Given, $(-2x+3y+2z{)}^2$
Using Identity,
$(a+b+c{)}^2=a^2+b^2+c^2+2ab+2bc+2ca$
$\therefore (-2x+3y+2z{)}^2$
$=(-2x{)}^2+(3y{)}^2+(2z{)}^2+2\times (-2x)\times (3y)+2\times (3y)\times (2z)+2\times (-2x)\times (2z)$
$=4x^2+9y^2+4z^2-12xy+12yz-8xz$

Hence, $(-2x+3y+2z{)}^2=4x^2+9y^2+4z^2-12xy+12yz-8xz.$