Question

Write the following into algebraic language.

Three-fourths of $x$ multiplied by difference of $x$ cube and $y$ square.

Answer 1

Write in algebraic language.

Given, three-fourths of $x$ multiplied by difference of $x$ cube and $y$ square.

Here,

Three-fourths of $x$ is $\frac{3}{4}\times x=\frac{3x}{4}$.

The difference of $x$ cube and $y$ square is $x^3-y^2$.

Now, three-fourths of $x$ multiplied by difference of $x$ cube and $y$ square is given by

$$\begin{gathered} =\frac{3x}{4}\times (x^3-y^2) \\ =\frac{3x(x^3-y^{2)}}{4} \end{gathered}$$

Hence, the final answer is $\frac{3x(x^3-y^{2)}}{4}$.