CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Monomial

Write the fol...

Question

Write the following monomials according to their degrees the ascending order
(a) $\frac{1}{5} x^{11}, - 5 x^{7}, 4, 5 x^{10}, 2 x^{3}, x, 9 x^{5}, 3 x^{2}$
(b) $6 x^{15}, 4 x^{2}, 9, x, 5 x^{6}, 7 x^{9}, 3 x^{3}$

Open in App

Solution

The degree of a polynomial is the highest degree of its terms when the polynomial is expressed in its canonical form consisting of a linear combination of monomials. The Ascending order of the given monomials are:
a. $\frac{1}{5} x^{11}, 5 x^{10}, - 5 x^{7}, 9 x^{5}, 2 x^{3}, 3 x^{2}, x, 4$
b. $6 x^{15}, 7 x^{9}, 5 x^{6}, 3 x^{3}, 4 x^{2}, x, 9$

Note: 4 can be written as $4 x^{0}$ having the lowest degree and so is for 9

Suggest Corrections

thumbs-up

0

Similar questions

Q. Arrange the following limits in ascending order
a)

lim x \to 0 \frac{sin x^{0}}{x}

lim x \to 0 \frac{3 sin x^{0} - sin 3 x^{0}}{x^{3}}

lim x \to 0 \frac{t a n x^{0}}{2 x}

lim x \to 0 \frac{(sec x^{0} + 1) (sec x^{0} - 1)}{x^{2}}

Q. Arrange the type of angles according to their degree in ascending order from top to bottom.

Q. Write the monomial in x, having degree

5

Q. Arrange the following limits in the ascending order
a)

lim x \to 0 {(\frac{1^{x} + 2^{x} + 4^{x}}{3})}^{\frac{1}{x}}

lim x \to 0 {(\frac{2^{x} + 3^{x} + 8^{x} + 27^{x}}{4})}^{\frac{1}{x}}

lim x \to 0 {⎡ ⎣ \frac{1^{x} + (\frac{1}{2})^{x} + (\frac{1}{4})^{x}}{3} ⎤ ⎦}^{\frac{1}{x}}

lim x \to 0 {⎡ ⎣ \frac{(\frac{1}{2})^{x} + (\frac{1}{3})^{x} + (\frac{1}{8})^{x} + (\frac{1}{27})^{x}}{4} ⎤ ⎦}^{\frac{1}{x}}

Q. For each of the following monomials , write its degree :

- 2 p^{2} q^{3} r^{4}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Introduction

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard VIII Mathematics

Join BYJU'S Learning Program

CrossIcon