Question

Write the following numbers in their usual form:

$4\times {10}^8+3\times {10}^6+5\times {10}^5+9\times {10}^3+7\times {10}^2+6\times {10}^1$

Answer 1

Converting exponential form of number into usual form:

Given number: $4\times {10}^8+3\times {10}^6+5\times {10}^5+9\times {10}^3+7\times {10}^2+6\times {10}^1$

We know that, for converting number in usual form we have to multiply the terms in expanaded form and add them.

Using the above criteria for converting in usual form:

$4\times {10}^8+3\times {10}^6+5\times {10}^5+9\times {10}^3+7\times {10}^2+6\times {10}^1$

$$\begin{gathered} =4\times 10,00,00,000+3\times 10,00,000+5\times 1,00,000+9\times 1,000+7\times 100+6\times 10 \\ =40,00,00,000+30,00,000+5,00,000+9,000+700+60 \\ =40,35,09,760 \end{gathered}$$

Hence, $40,35,09,760$ is the required usual form the number.