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Question

Write the following polynomial in coefficient form.
(i) x4 + 16 (ii) m5 + 2m2 + 3m + 15

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Solution


(i)
x4+16=x4+0x3+0x2+0x+16

Therefore, the given polynomial in coefficient form is (1, 0, 0, 0, 16).

(ii)
m5+2m2+3m+15=m5+0m4+0m3+2m2+3m+15

Therefore, the given polynomial in coefficient form is (1, 0, 0, 2, 3, 15).

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