Write the following polynomials in the standard form (descending type) : $7 x + 4 x^{2} + \sqrt{3} x^{3} - 14$

\sqrt{3} x + 4 x^{2} + 7 x - 14

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{3} x^{3} + 4 x^{2} + 7 x - 14

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\sqrt{3} x^{3} + 4 x^{2} + 7 x + 14

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{4} x^{3} + 4 x^{2} + 7 x - 14

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\sqrt{3} x^{3} + 4 x^{2} + 7 x - 14$
A polynomial function is in standard form if its terms are written in descending order of exponents from left to right.
$7 x + 4 x^{2} + \sqrt{3} x^{3} - 14$
$= \sqrt{3} x^{3} + 4 x^{2} + 7 x - 14$

Suggest Corrections

Similar questions

-

-

\sqrt{5}

\frac{11}{8} x^{2} + 2 - 7 x

\sqrt{3} x^{3} - 14

3 x^{3} - 4 x^{2} + 7 x - 5

x = 3

x = - 3

3 x^{3} - 4 x^{2} + 7 x - 5

x^{5} + 2 x^{4} + 3 x^{3} + x^{2} - 7 x + 8

x^{5} + 2 x^{4} + 3 x^{3} + x^{2} - 7 x + 8

Join BYJU'S Learning Program