Question

Write the following rational numbers so that they have same denominator:

$\frac{3}{40},\frac{7}{10},\frac{15}{-80}$

Answer 1

Converting given fraction into equivalent fractions.

First we convert $\frac{15}{-80}$ into standard form by multiplying numerator and denominator by $-1$ so, it will become $\frac{-15}{80}$ .

To convert them in equivalent fraction we have to take the LCM of the denominators.

So, LCM of $40,10$ and $80$ is $80$.

Now convert the given rational numbers in equivalent fraction with denominator $80$.

$\Rightarrow \frac{3\times 2}{40\times 2}=\frac{6}{80},\frac{7\times 8}{10\times 8}=\frac{56}{80}$ and $\frac{-15\times 1}{80\times 1}=\frac{-15}{80}$

Now we can see that $\frac{6}{80},\frac{56}{80}$ and $\frac{-15}{80}$ have the same denominator.

Hence, $\frac{3}{40},\frac{7}{10},\frac{15}{-80}=\frac{6}{80},\frac{56}{80},\frac{-15}{80}$.