Write the following redox reactions in the oxidation and reduction half reaction (i)2K+Cl2=2KCl
(ii) 2Al+3Cu²⁺=2Al³+3Cu

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Solution

Dear student,

In oxidation, there is loss of electrons and in reduction, there is a gain of electrons

1.Oxidation and reduction half cell reaction are as follows :
$K \to K C l + e^{-} C l_{2} + 2 e^{-} \to 2 K C l$

2. oxidation : $A l \to A l^{3 +} + 3 e^{-}$
reduction : $C u^{2 +} + 2 e^{-} \to C u$

Regards

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The oxidation and reduction half reactions of the reaction

2Al_(s) + 3Cu²⁺_(aq) → 2Al³⁺_(aq) + 3Cu_(s) are

{2 K}_{2} M n O_{4} + {C l}_{2} ⟶ 2 K C l + 2 K M n O_{4}

Divide the following redox reactions into oxidation and reduction half reactions.

(i) $Z n + P b^{2} \to Z n^{2} + P b$

(ii) $Z n + C u^{2 +} \to Z n^{2} + C u$

(iii) $C l_{2} + 2 B r^{-} \to B r_{2} + 2 C l^{-}$

write down the reduction and oxidation half reactions of the reaction: Na(s)+F(g),----->NaF

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