wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Write the following squares of binomials as trinomials:
(i) (x + 2)2
(ii) (8a + 3b)2
(iii) (2m + 1)2
(iv) 9a+162
(v) x+x222
(vi) x4-y3
(vii) 3x-13x2
(viii) xy-yx2
(ix) 3a2-5b42
(x) (a2b − bc2)2
(xi) 2a3b+2b3a2
(xii) (x2 − ay)2

Open in App
Solution

We will use the identities a+b2=a2+2ab+b2 and a-b2=a2-2ab+b2 to convert the squares of binomials as trinomials.

(i) x+22=x2+2×x×2+b2=x2+4x+b2

(ii) 8a+3b2=8a2+28a3b+6b2=64a2+48ab+36b2

(iii) 2m+12=2m2+22m1+12=4m2+4m+1

(iv) 9a+162=9a2+29a16+162=81a2+3a+136

(v) x+x222=x2+2xx22+x222=x2+x3+x44

(vi) x4-y32=x42-2x4y3+y32=x216-16xy+y29


(vii) 3x-13x2=3x2-23x13x+13x2=9x2-2+19x2

(viii) xy-yx2=xy2-2xyyx+yx2=x2y2-2+y2x2


(ix) 3a2-5b42=3a22-23a25b4+5b42=9a24-15ab4+25b216

(x) a2b-bc22=a2b2-2a2bbc2+bc22=a4b2-2a2b2c2+b2c4




(xi) 2a3b+2b3a2=2a3b2+22a3b2b3a+2b3a2=4a29b2+89+4b29a2



(xii) x2-ay2=x22-2x2ay+ay2=x4-2x2ay+a2y2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon