Write the following statement in inequality
2 added to thrice a number is greater than or equal to 15; Take the number as x

$2 x + 3 > 15$

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$2 x - 3 < 15$

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$3 x + 2 \geq 15$

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$3 x + 2 \leq 15$

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Solution

The correct option is C
$3 x + 2 \geq 15$

Thrice the number (x) = 3x ;

two added to the number = 3x + 2

Greater than or equal to 15 ;

Hence $3 x + 2 \geq 15$

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Similar questions

Tick $(✓)$ the correct answer in each of the following:

$(x + 5) (x - 3) = ?$

(a) $x^{2} + 5 x - 15$
(b) $x^{2} - 3 x - 15$
(c) $x^{2} + 2 x + 15$
(d) $x^{2} + 2 x - 15$

9 x^{2} - 16 y^{2} = 144

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