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Question

Write the following statement in symbolic form and find its truth value:
nϵN,n2+n is an even number and n2n is an odd number

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Solution

nN
p:n2+n is a even number
q:n2n is an odd number.
Then, n2+n is a even number and n2n is an odd number.
It can also be written as:
pq

Now,
n2+n=n(n+1), product of two continuous natural numbers is always even, Hence, p is True.
n2n=n(n1), product of two continuous natural numbers is always even, Hence, q is False.

Hence, pq is False.

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