Question

Write the following using positive exponents only :

$\frac{{\left(-3\right)}^0\times {\left(2^2\right)}^{-2}\times 9^2}{{\left(5^2\right)}^{-3}\times 3^2}$

Answer 1

Given that, $\frac{{\left(-3\right)}^0\times {\left(2^2\right)}^{-2}\times 9^2}{{\left(5^2\right)}^{-3}\times 3^2}$

$=\frac{1\times 2^{2\times -2}\times 9^2}{5^{2\times -3}\times 3^2}$

$=\frac{2^{-4}\times {\left(3^2\right)}^2}{5^{-6}\times 3^2}$

$=\frac{3^4\times 5^6\times 3^{-2}}{2^4}$

$=\frac{3^2\times 5^6}{2^4}$

Hence , the required value is $\frac{3^2\times 5^6}{2^4}$.