We have,
(5x−3y)3
We know that
(a−b)3=a3−b3−3ab(a−b)
Therefore,
(5x−3y)3=(5x)3−(3y)2−3×5x×3y(5x−3y)
(5x−3y)3=125x3−27y3−45xy(5x−3y)
(5x−3y)3=125x3−27y3−225x2y+135xy2
Hence, this is the answer.