Question

Write the formula of angle of minimum deviation produced by a thin prism.

Answer 1

For thin prism relation is given by,

$n_{\lambda }=\frac{sin\frac{A+D_{\lambda }}{2}}{sin\frac{A}{2}}$

where $n$ is the refractive index at a wavelength $\lambda$, $D$ is the angle of minimum deviation, and $A$ is the internal angle of the prism.