Write the formula of calcium ion with phosphate, sulphate and hydrogen carbonate ions.

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Solution

$C a^{2} P {O_{4}}^{3} C r o s s m u l t i p l y = C a_{3} (P O_{4})_{2} c a l l e d C a l c i u m p h o s p h a t e C a^{2} S O_{4} 2 C r o s s m u l t i p l y = C a_{2} (S O_{4})_{2} = C a S O_{4} c a l l e d C a l c i u m s u l p h a t e C a^{2} H C {O_{3}}^{1} C r o s s m u l t i p l y = C a_{1} (H C O_{3})_{2} = C a (H C O_{3})_{2} c a l l e d C a l c i u m b i c a r b o n a t e$

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Write the formula of calcium ion with phosphate, sulphate and hydrogen carbonate ions.

Ca2 PO43Cross multiply = Ca3(PO4)2 called Calcium phosphateCa2 SO42Cross multiply = Ca2(SO4)2 = CaSO4 called Calcium sulphateCa2 HCO31Cross multiply = Ca1(HCO3)2 = Ca(HCO3)2 called Calcium bicarbonate