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Question

Write the formula of the following compounds:
(i) Potassium trioxalatoaluminate (III)
(ii) Hexaaquairon(II) sulphate.


Solution

The formula of the compounds is given below.
(i) Potassium trioxalatoaluminate (III)
$$\displaystyle K_3 [Al(C_2O_4)_3]$$
Oxalate ion has $$\displaystyle -2$$ charge. 3 oxalate ions have $$\displaystyle -2 \times 3 = -6$$ charge which is balanced with $$\displaystyle +3$$ charge on one Al ion and $$\displaystyle +3$$ charge on 3 K ions (each K ion has $$\displaystyle +1 $$ charge).
(ii) Hexaaquairon(II) sulphate.
$$\displaystyle [Fe(H_2O)_6]SO_4$$
It has 6 water ligands. The $$\displaystyle -2$$ charge on sulphate ions is balanced with +2 charge on ferrous ion.

Chemistry

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