Question

Write the forward and backward reaction of this chemical equation:
$2\mathrm{NaCl}\left(\mathrm{aq}\right)+{\mathrm{CaCO}}_3\left(s\right)\to {\mathrm{Na}}_2{\mathrm{CO}}_3\left(\mathrm{aq}\right)+{\mathrm{CaCl}}_2\left(\mathrm{aq}\right)$

Answer 1

So in this reaction nitrogen gas combines with hydrogen to form ammonia gas which is our forward reaction. So our reactants are nitrogen and hydrogen while ammonia is our product.

$N_2\left(g\right)+3H_2\left(g\right)\to 2{\mathrm{NH}}_3\left(g\right)$ is forward reaction.

The product of a forward reaction becomes the reactant of a backward reaction. So in backward reaction, we can write ammonia which dissociates to nitrogen and hydrogen.

$2{\mathrm{NH}}_3\left(g\right)\to N_2\left(g\right)+3H_2\left(g\right)$ is backward reaction.