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Byju's Answer
Standard XII
Chemistry
Idea of Hybridisation
Write the hyb...
Question
Write the hybridization and number of unpaired
e
−
in the complex
[
C
o
F
e
]
3
−
.
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Solution
Hybridization in the complex
[
C
o
F
6
]
3
−
is
s
p
3
d
2
because fluorine is a weak field ligand.
The number of unpaired electrons is 4.
The electronic configuration of Co is
[
A
r
]
4
s
0
3
d
6
.
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Similar questions
Q.
What is the hybridization state and number of unpaired electrons of
F
e
atom in
[
F
e
F
6
]
3
−
complex?
Q.
In
[
C
o
F
6
]
3
−
,
C
o
3
+
uses outer d orbits (4d) in
s
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d
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hybridization. The number of unpaired electrons present in complex ion is :
Q.
Write the hybridisation and number of unpaired electrons in the complex
[
C
o
F
6
]
3
−
. (Atomic No. of Co
=
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).
Q.
Nickel
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Z
=
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combines with a uninegative monodentate ligand to form a diamagnetic complex
[
N
i
X
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]
2
−
. The hybridization involved and the number of unpaired electrons present in the complex is respectively:
Q.
In hexacyanomanganate (II) ion, the
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