Write the least positive integeral vlaue of n for which (1+i1−i)n is real.
For n = 1
(1+i1−i)1=1+i1−i=1+i1−i×1+i1+i=(1+i)212+12=12+i2+2i2=1−1+2i2=2i2=iFor n = 2(1+i1−i)2=(i)2=−1, which is real
Hence least positive integral value of n is 2.
Find the least positie integral value of n for which (1+i1−i)n is real.
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