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Question

Write the maximum value of 12 sin θ − 9 sin2 θ.

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Solution

Let fθ=12sinθ -9 sin2θ =-9sin2θ-12 sin θ = -3sin θ2-2.3 sin θ.2+22-4 =-3 sinθ-22-4 =4-3 sinθ-22Minimum value of 3 sinθ-22 is 0.Therefore, maximum value of 4-3 sinθ-22 would be 4.

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