Write the mechanism of the reaction of $H I$ with methoxybenzene.

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Solution

The mechanism for the reaction of $H I$ with methoxybenzene involves $2$ steps.

$Protonation of methoxybenzene .$

$Attack of the nucelophile on the protonated methoxybenzene .$

On cleavage, methoxybenzene gives phenol and methyl iodide as the products.

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