Write the mechanism of the reaction of $H I$ with methoxymethane.

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Solution

The mechanism of the reaction of $H I$ with methoxymethane is shown below:
Fist step is the protonation of methoxymethane. Second step is the nucleophilic attack of iodide ion to form iodomethane and methanol.
If $H I$ is present in excess and if temperature is high, methanol reacts with HI to form methyl iodide.

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