Write the median clas of the following distribution:
Class0−1010−2020−3030−4040−5050−6060−70Frequency448101284
Class | Mid-point(x) | Frequency(f) | (fx) | Cumulative frquency | ||||
0-10 | 5 | 4 | 20 | 4 | ||||
10-20 | 15 | 4 | 60 | 4+4=8 | ||||
20-30 | 25 | 8 | 200 | 8+8=16 | ||||
30-40 | 35 | 10 | 350 | 16+10=26 | ||||
40-50 | 45 | 12 | 540 | 26+12=38 | ||||
50-60 | 55 | 8 | 440 | 38+8=46 | ||||
60-70 | 65 | 4 | 260 | 46+4=50 | ||||
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Mean = ∑fx∑f=187050 = 37.4
A median group is in the range of 30 - 40, as we have mean 37.4
And
Formula for median = L+N2−Cfbfm×w
Here
L is the lower class boundary of the group containing the median = 30
n is the total number of data = 50
c (fb) is the cumulative frequency of the groups before the median group = 16
(fm) is the frequency of the median group = 10
w is the group width = 10
So,
Median = 30+502−1610×10 = 30+ 25 - 16 = 39