Write the molecular formulae of all the compounds that can be formed by the combination of following ions.
$C u^{2 +}, N a^{+}, C l^{-}, S O_{4}^{2 -}, F e^{3 +}$

C u C l_{2} / C u S O_{4}

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N a C l / N a_{2} S O_{4}

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F e C l_{3} / F e_{2} (S O_{4})_{3}

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All of the above

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Solution

The correct option is D All of the above
Compounds are formed by the combination of cation and anion.
On combining all the possible positive ions with negative ions, we get
$C u C l_{2}, C u S O_{4}, N a C l, N a_{2} S O_{4}, F e C l_{3}, F e_{2} (S O_{4})_{3}$

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Question 13
Write the molecular formulae of all the compounds that can be formed by the combination of following ions
$C u^{2 +}, N a^{+}, F e^{3 +}, C l^{-}, S O_{4}^{2}, P O_{4}^{3 -}$

Question 13
Write the molecular formulae of all the compounds that can be formed by the combination of following ions
$C u^{2 +}, N a^{+}, F e^{3 +}, C l^{-}, S O_{4}^{2}, P O_{4}^{3 -}$

Q. The molecular formulae of all the possible compounds formed from given ions are:

(N a^{+}, M g^{2 +}, C l^{-}, S O_{4}^{2 -})

Q. A compound, on analysis, gave the following percentage composition :

N a = 14.31 %, S = 9.97 %, H = 6.22 %, O = 69.5 %

What would be the molecular formula of the compound assuming that all the hydrogen in the compound is reset in combination with oxygen as water of crystallisation. Molecular weight of the compound is

322

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Write the molecular formulae of all the compounds that can be formed by the combination of following ions.Cu2+,Na+,Cl−,SO2−4,Fe3+

The correct option is D All of the aboveCompounds are formed by the combination of cation and anion.On combining all the possible positive ions with negative ions, we getCuCl2,CuSO4,NaCl,Na2SO4,FeCl3,Fe2(SO4)3

Write the molecular formulae of all the compounds that can be formed by the combination of following ions.
$C u^{2 +}, N a^{+}, C l^{-}, S O_{4}^{2 -}, F e^{3 +}$

The correct option is D All of the above
Compounds are formed by the combination of cation and anion.
On combining all the possible positive ions with negative ions, we get
$C u C l_{2}, C u S O_{4}, N a C l, N a_{2} S O_{4}, F e C l_{3}, F e_{2} (S O_{4})_{3}$