Write the name and formula of the $2^{n d}$ member of the series of the carbon compounds, whose general formula is $C_{n} H_{2 n}$ .

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Solution

General formula $C_{n} H_{2 n} ⟶$ Alkene
$n = 2, C_{2} H_{4}$ $C H_{2} = C H_{2} ⟶$ $1^{s t}$ member
$n = 3, C_{3} H_{6}$ $C H_{3} - C H = C H_{2} ⟶ 2^{n d}$ member
$P r o p e n e$

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(c) Name any two fossil fuels.

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Write the name and formula of the 2nd member of the series of the carbon compounds, whose general formula is CnH2n.

General formula CnH2n⟶ Alkenen=2,C2H4 CH2=CH2⟶ 1st membern=3,C3H6 CH3−CH=CH2⟶2nd member Propene

Write the name and formula of the $2^{n d}$ member of the series of the carbon compounds, whose general formula is $C_{n} H_{2 n}$ .

General formula $C_{n} H_{2 n} ⟶$ Alkene
$n = 2, C_{2} H_{4}$ $C H_{2} = C H_{2} ⟶$ $1^{s t}$ member
$n = 3, C_{3} H_{6}$ $C H_{3} - C H = C H_{2} ⟶ 2^{n d}$ member
$P r o p e n e$