Write the name of the following compound :
$H_{3} C - {CH}_{2} - {CH}_{2} - {CH}_{2} - C \equiv C - H$

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Solution

Step 1: Determination of root word
Select the continuous chain with the maximum number of Carbon atoms.
Here the chain is having $6$ Carbon atoms, hence the root word will be ‘Hex’
$H_{3} \overset{6}{C} - \overset{5}{C} H_{2} - \overset{4}{C} H_{2} - \overset{3}{C} H_{2} - \overset{2}{C} \equiv \overset{1}{C} - H$
Step 2: Determination of names and positions of locants
There is one substituent (Triple bond ( $\equiv$ )) at $1$ position.
Step 3:Determination of Suffix
As this hydrocarbon is unsaturated with a triple bond hence, the suffix will be ‘yne’
Name of the compound: 1-Hexyne.

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Similar questions

(i) Write the IUPAC name of the following compounds.
$C H_{3} - C H | C H_{3} - C H | O H - C H | C_{2} H_{5} - C H | O H - C H_{3}$

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Study the given paragraph(s) and answer the following questions.

Passage:

Markownikoff’s Rule:

When an unsymmetrical alkene or alkyne reacts with an unsymmetrical reagent, then the negative part of the reagent attaches to that carbon atom which contains a lesser number of hydrogen atoms during the addition.

For example:

${CH}_{3} CH = {CH}_{2} + HBr \to {CH}_{3} CH (Br) {CH}_{3}$

${CH}_{2} = {CH}_{2} + HBr \to {CH}_{3} {CH}_{2} Br$

Markownikoff’s Addition:

The addition of $HBr$ (not $HCl, HI and HF$ ) on alkenes in presence of peroxides takes place in anti-Markownikoff’s way (Peroxide effect).

${CH}_{3} CH = {CH}_{2} + HBr (peroxide) \to {CH}_{3} {CH}_{2} CHBr$

Question statement:

Markownikoff’s addition is applicable to

Q. (i) Write IUPAC name of the following compound:

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Write the name of the following compound :H3C-CH2-CH2-CH2-C≡C-H

Write the name of the following compound :
$H_{3} C - {CH}_{2} - {CH}_{2} - {CH}_{2} - C \equiv C - H$