Question

Write the natural numbers from $102$ to $113$. What fraction of them are prime numbers?

Answer 1

The natural numbers from $102$ to $113$ are $102,103,104,105,106,107,108,109,110,111,112,113$

Total number of natural numbers are $12$(whole)

In that the prime numbers are $103,107,109,113$

Total number of prime numbers is $4$(part)

To find the fraction of them, We know that

$$\begin{gathered} Fraction=\frac{Part}{Whole} \\ \therefore Fraction=\frac{4}{12} \\ =\frac{1}{3} \end{gathered}$$

Hence, the fraction of them are prime numbers is $\frac{4}{12}$ or $\frac{1}{3}$